Question

`\bold{Heya...}`


`\mathtt{9 \: - \: 3}` ÷
`\mathtt{(1)/(3) \: 1 \: ?}`

Explain into your own words.

Thanks~

Answer 1

`{ \qquad\qquad\huge\underline{{\sf Answer}}}`

Let's proceed according to Bodmas rule ~

`\qquad \sf  \dashrightarrow \:9 - 3 / (1)/(3) 1`

[ as 3 ÷ 1/3 = 3 × 3 = 9 ]

`\qquad \sf  \dashrightarrow 9 - 9`

`\qquad \sf  \dashrightarrow \:0`

So, by simplification we will get 0 as our result.

Answer 2

Heyo!

I believe you mess up your fraction.

Let's do this step-by-step explanation.

`9-(3)/(1(1)/(3) )`

=
`9-(3)/((4)/(3) )`

=
`9-(9)/(4)`

=
`(27)/(4)`

=
`6 (3)/(4)`

Answer:

`6 (6)/(4)`

Hopefully, this helps you!!

`HawtieNoya`