Answer:
![Probability=(3)/(125)](https://img.qammunity.org/2020/formulas/mathematics/high-school/o2jouou57i7yyvf57tlq1qrbud3xow68ig.png)
Explanation:
In the question,
Total number of pieces of paper numbered from 1 to 25 are = 25
As the draw also includes replacement.
So,
Probability of drawing '3' is given by,
![Probability=(Favourable\,outcomes)/(Total\,cases)\\Probability=(1)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/dlxrttgkm2qqdd31nqtroyl2130ccua3dz.png)
Now,
Numbers greater than 10 are = 15
So,
Probability of drawing a number greater than 10 is given by,
![Probability=(15)/(25)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mlptnap9lxj5elwp3r6fxwwd9o7cfkl3jz.png)
So,
Total probability is given by,
Product of probability of drawing 3 in 1st draw and the Probability of drawing a number greater than 10.
![(1)/(25)* (15)/(25)=(3)/(125)\\Probability=(3)/(125)](https://img.qammunity.org/2020/formulas/mathematics/high-school/q1gcz6vckc7j72xz341jva92nv3j0sq81r.png)