Answer:
![P(F) = 0.515](https://img.qammunity.org/2022/formulas/mathematics/high-school/vb9jmrweif3vr1y57s957bp03ijwhyfsn1.png)
![P(M) = 0.485](https://img.qammunity.org/2022/formulas/mathematics/high-school/oagle3ld0goydti8fick1bgemdml7bfvrk.png)
Step-by-step explanation:
Given
![Female = 51.5\%](https://img.qammunity.org/2022/formulas/mathematics/high-school/1jwebil0ad9677lcleyislvdwc22fjowsb.png)
Solving (a): Probability of running into a female
To do this, we simply convert the given proportion to decimal
![P(F) = 51.5\%](https://img.qammunity.org/2022/formulas/mathematics/high-school/vj8v2jlahdcxscoza59gu49fy7acwsb4wf.png)
Convert to fraction
![P(F) = (51.5)/(100)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ln0y2ll1jbbbgvr7shtb9xd3w91t8denq4.png)
![P(F) = 0.515](https://img.qammunity.org/2022/formulas/mathematics/high-school/vb9jmrweif3vr1y57s957bp03ijwhyfsn1.png)
Solving (b): Probability of running into a male
Represent this with
![P(M)](https://img.qammunity.org/2022/formulas/mathematics/high-school/djczjrigrttmljep87j6p0ll2fgryyw07f.png)
To solve this, we apply the concept of probability complement which states that:
![p + q = 1](https://img.qammunity.org/2022/formulas/mathematics/college/k2sn5eda198wf1crwed4qpica7emjfc8hr.png)
In this case:
![P(F) + P(M) = 1](https://img.qammunity.org/2022/formulas/mathematics/high-school/tfgfuozbwguoqquwp3ivwgrfynt73fmg2q.png)
Substitute 0.515 for P(F)
![0.515 + P(M) = 1](https://img.qammunity.org/2022/formulas/mathematics/high-school/yrbdgvgajcc9m4b3vdumvady8rj68i7es6.png)
Subtract 0.515 from both sides
![0.515-0.515 + P(M) = 1 - 0.515](https://img.qammunity.org/2022/formulas/mathematics/high-school/62g5o5nq1iu53a8mlm0jzoq2ylc3zulhrx.png)
![P(M) = 1 - 0.515](https://img.qammunity.org/2022/formulas/mathematics/high-school/dgccc6bx3869lbbn10t5pvds4un3aqksm2.png)
![P(M) = 0.485](https://img.qammunity.org/2022/formulas/mathematics/high-school/oagle3ld0goydti8fick1bgemdml7bfvrk.png)