Question

A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starting point of the ball, and whose y axis points vertically upward. Neglecting air resistance, calculate the ve- locity of the ball after 3.04 s. The acceleration of gravity is 9.8 m/s2 . Answer in units of m/s.

Answer 1

To find the velocity of a released golf ball after 3.04 seconds in free fall with no air resistance, we use the equation v = u + at with u=0 m/s, a=-9.8 m/s², and t=3.04 s, yielding v = -29.792 m/s, denoting downward motion.

Step-by-step explanation:

To calculate the velocity of the golf ball after it has been released and fallen for 3.04 seconds, we can use the equation of motion for uniformly accelerated motion (since we're neglecting air resistance). The coordinate system is chosen such that the y-axis points vertically upward, with the origin at the starting point of the ball.

The equation to use is: v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity, and t is the time.

Given:
Initial velocity, u = 0 m/s (since the ball is released from rest)
Acceleration, a = -9.8 m/s2 (the negative sign indicates the direction of acceleration is opposite to the chosen positive direction)
Time, t = 3.04 s

Inserting these values into the equation, we get:
Final velocity, v = 0 m/s + (-9.8 m/s2) * 3.04 s
Final velocity, v = -29.792 m/s

Note: The negative sign indicates that the velocity is directed vertically downward.

Answer 2

Answer:
`v=29.792m.s^(-1)`

Step-by-step explanation:

Here given that:

• initial velocity of the golf ball,
  `u =0m.s^(-1)`
• a coordinate system pointing upwards with origin at the point of release.
• time, t = 3.04 seconds
• acceleration due to gravity,
  `g = 9.8 m.s^(-2)`

Now, we need to find the velocity (v) after the time 3.04 s.

From the given and required data we choose the suitable equation of motion:
`v = u+at`

Putting the given values in the above equation:

`v= 0 - gt` ∵the given frame of reference points in the upward directoin so we have negative on the downward side.

`v=0-9.8* 3.04`

`v=29.792m.s^(-1)`