Question

Find the x- and y- intercepts of the following equation.

-3x + 4y = -12

y - intercepts : (0,4)
x - intercepts : (-3,0)

y - intercepts : (0,-6)
x - intercepts : (-3,0)

y - intercepts : (0,-6)
x - intercepts : (-4,0)

y - intercepts : (0,-3)
x - intercepts : (4,0)

Answer 1

The x-intercept is
`(4,0)`

The y-intercept is
`(0,-3)`

Explanation:

Suppose you have a function f:

`f = f(x,y) = 0`

The x-intercept is the value of x when
`y = 0`.

The x-intercept is the value of y when
`x = 0`.

Solution

We have:

`f(x,y) = -3x + 4y = -12`

`-3x + 4y + 12 = 0`

x-intercept

The x-intercept is the value of x when
`y = 0`. So:

`-3x + 4(0) + 12 = 0`

`-3x + 12 = 0`*(-1)

`3x - 12 = 0`

`3x = 12`

`x = (12)/(3)`

`x = 4`

The x-intercept is
`(4,0)`

y-intercept

The y-intercept is the value of y when
`x = 0`. So:

`-3(0) + 4y + 12 = 0`

`4y + 12 = 0`

`4y = -12`

`y = (-12)/(4)`

`y = -3`

The y-intercept is
`(0,-3)`