Question

Two inductors are connected in parallel to a 120 volt, 60 Hz line. The values are 5 H and 2 H. The total inductive reactance is

Answer 1

Answer:Total Inductive reactance XL =538.63 Ω

Step-by-step explanation:

Parallel combination for Effective inductance is calculated as

L total =
`(1)/(1/L1 + 1/L2 + ... 1/Ln)`

=
`(1)/(1/5 + 1/2)`

`(1)/(0.2 + 0.5 \\)`

=
`(1)/(0.7)`

=1.42857H

Inductive reactance XL = 2 πFL

where f= frequency= 60Hz

L= Effective inductance=1.42857H

Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857

=538.63Ω