Answer:
The temperature will be 93.92 °C
Step-by-step explanation:
To explain this we will use following equation: also Q = ∆U + W known as the NON-FLOW ENERGY EQUATION (N.F.E.E.)
With Q = heat added to the system
with ∆U = change in internal energy
⇒∆U = ( m )( Cv )( T2 - T1 )
With W = work done by the system
⇒For this situation W = 0 because there isn't work done
So we get: ∆U = ( m )( Cv )( T2 - T1 ) = Q
To find the temperature, we have to isolate T in the equation:
(T2-T1) = Q / (m)(Cv)
⇒ Since we know that m = density * volume we can calculate the mass of water.
mass = 1000g/L * 1.16 L = 1160g
Cv = heat capacity ⇒ water has a heat capacity of 4.184 J/g °C
We know the absorption of heat is 9.4x 10^-2 kWh but to know how many joule this is we should convert ( 1 joule = 3.6 x 10^6 kWh)
⇒Q = ( 0.094 kWh ) ( 3.6 x 10^6 J / kWh ) = 0.3384 x 10^6 J
For the temperature we get then: T2 -T1 = Q / (m)(Cv)
T2 - T1 = 0.3384 x 10^6 J / (( 1160g)*(4.184 J/g °C)) = 69.72 ° C
T2 = ( T2 - T1 ) + T1 ⇒ 69.72 + 24.2 = 93.92 °C