Answer: (1) 14.4% (2) 3.78% (3) $222.48 (4) 21,176.47
(5) $425 (6) 14.3 cents per mile
Explanation:
1) This is a calculator question. I = 0.144 --> 14.4%
![A=P\bigg(1+(r)/(n)\bigg)^(nt)\\\\\bullet \text{A = Accrued amount (total amount paid)}\\\bullet \text{P = Principal (initial cost of the car)}\\\bullet \text{r = rate (interest rate in decimal form)}\\\bullet \text{n = number of times in a year (number of months)}\\\bullet \text{t = number of years}\\\\A = m * nt\\\bullet \text{m = monthly payment amount}\\\bullet \text{nt = number of payments made}\\\implies m* nt=P\bigg(1+(r)/(n)\bigg)^(nt)](https://img.qammunity.org/2020/formulas/mathematics/high-school/tp72weium4736j6ml6d33yfkx4o0nb95ek.png)
2) m = 93.33
nt = 36
P = 3000
n = 12
![m* nt=P\bigg(1+(r)/(n)\bigg)^(nt)\\\\\\93.33* 36=3000\bigg(1+(r)/(12)\bigg)^(36)\\\\\\3359.88=3000\bigg(1+(r)/(12)\bigg)^(36)\\\\\\1.11996=\bigg(1+(r)/(12)\bigg)^(36)\\\\\\1.00315198=1+(r)/(12)\\\\\\0.00315198=(r)/(12)\\\\\\0.0378=r\\\\\\\large\boxed{3.78\%}=r](https://img.qammunity.org/2020/formulas/mathematics/high-school/c7m4xxow8dlw13ofy323q0oqx2tee9373f.png)
3) same equation as #2 but deduct the down payment from the Principal
nt = 42
P - d = 5,555 - 555 = 5,000
r = 18% --> 0.18
n = 12
![m* nt=P\bigg(1+(r)/(n)\bigg)^(nt)\\\\\\m* 42=(5,555-555)\bigg(1+(.18)/(12)\bigg)^(42)\\\\\\42m=5000(1.015)^(42)\\\\\\42m=5000(1.868847)\\\\\\42m=9344.23557\\\\\\m=\large\boxed{222.48}](https://img.qammunity.org/2020/formulas/mathematics/high-school/yom57acnvj8vm09gf95rsoxs6ju4vze7um.png)
4) Gas + Oil = cost per mile × number of miles
1000 + 800 = 0.085x
1800 = 0.085x
![\large\boxed{21,176.47}=x](https://img.qammunity.org/2020/formulas/mathematics/high-school/5lvc1m85yf0ei2c5slm27eub852dd8yavp.png)
5)
![\text{Annual Depreciation}=\frac{\text{Cost of car - Trade-in value}}{\text{Years driven}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/8p0tcltrog63s5sd8grlmkehxu6o4q3vfi.png)
![.\qquad =(3800-1250)/(6)\\\\\\.\qquad =(2550)/(6)\\\\\\.\qquad = \large\boxed{425}](https://img.qammunity.org/2020/formulas/mathematics/high-school/pqf5lk59k7ph2uc4b3lbqv8u17yspp0fko.png)
6)
![\frac{\text{(Cost of car - Market value) + Gas & Oil + Parts, Maintenance + Insurance}}{\text{Miles driven}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/39i64ecc269zgm3cdysoow9n51pxcnlxel.png)
![=((5000-3800)+750+250+300)/(17,500)\\\\\\=(2500)/(17,500)\\\\\\=0.142857\\\\=\large\boxed{14.3\ cents\ per\ mile}](https://img.qammunity.org/2020/formulas/mathematics/high-school/3i9p2zmuvtq9uvz3izdh9f0urfxu5kv878.png)