Question

A lead fishing weight with a mass of 57 g absorbs 146 cal of heat If its initial temperature is 48 ∘C, what is its final temperature?

Answer 1

132 ℃ is the final temperature.

Step-by-step explanation:

`Q = m * c * \Delta T`

where ∆T =final T- initial T

Q is the heat energy in calories = 146cal

c is the specific heat capacity

(for Lead (0.128 J/(g℃)) or (0.0305 cal/(g℃)

m is the mass of lead = 57g

Initial temperature is 48℃

Plugging in the values

146cal = 57g × 0.0305 cal/(g℃) × (final T - 48℃)

`\frac {146cal}{(57g*0.0305 cal/(g℃))} = final T-48^\circ{C}`

83.98℃ = final T - 48℃

So,

Final T = 83.98℃ + 48℃

Final T = 131.98℃ = 132℃ (Answer)

Answer 2

The final temperature is 130.6°, at the end of the process.

Step-by-step explanation: