Question

PLEASE HELP! I REALLY AM CONFUSED

Answer 1

`\log_7(x^2+4x-11)=\frac52`

`7^(\log_7(x^2+4x-11))=7^(\frac52)`

`x^2+4x-11=7^(\frac52)`

`x^2+4x-\left(11+7^(\frac52)\right)=0`

Now you can use the quadratic formula to solve for
`x`.

`x=-2\pm\sqrt{15+7^(\frac52)}`