Question

The perimeter of a rectangle is twice the sum of its length and it’s width . The perimeter is 22 meters and I it’s length is 2 meters more then twice it’s width. What’s its length?

Answer 1

The length of this rectangle is 8m.

Explanation:

The problem states that the perimeter of a rectangle is twice the sum of its length and it’s width. So

`P = 2*l + 2*w`

The problem also states that the perimeter is 22 meters. So:

`P = 22`

`2l + 2w = 22`.

Also, it states that I is the length and it is 2 meters more then twice it’s width. So

`l = 2w + 2`

What’s its length?

`P = 22`

`2l + 2w = 22`

`2(2w+2) + 2w = 22`

`4w + 4 + 2w = 22`

`6w = 22 - 4`

`6w = 18`

`w = (18)/(6)`

`w = 3`

The width is 3m. The length is in function of the width, so:

`l = 2w + 2`

`l = 2*3 + 2`

`l = 8m`

The length of this rectangle is 8m.