Answer:
10 number of checks.
Cost = $6
Explanation:
Given that:
Fixed Charges of first bank = $5
Charges of first bank per check = $0.10
Fixed Charges of second bank = $4
Charges of second bank per check = $0.20
To find:
Number of checks such that the charges for the banks become the same?
Solution:
Let the number of checks =
![x](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9sw50msm0inoav7spou76spw8zhpe27w2.png)
Cost for the first bank for
checks = $5 + $0.10
![x](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9sw50msm0inoav7spou76spw8zhpe27w2.png)
Cost for the second bank for
checks = $4 + $0.20
![x](https://img.qammunity.org/2022/formulas/mathematics/high-school/a9sw50msm0inoav7spou76spw8zhpe27w2.png)
As per question statement, both the costs are the same.
Comparing the values:
![5 + 0.10x = 4 + 0.20x\\\Rightarrow 0.10x = 1\\\Rightarrow x = 10](https://img.qammunity.org/2022/formulas/mathematics/college/9410iyvuh16t0cl17n23go80whvxgn1x87.png)
So, for 10 number of checks the cost will be same.
The cost = 4 + 0.20
10 = $6