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If a container of liquid contains 60 oz of solution, what is the number of ounces of pure acid if the given solution contains the following acid concentrations?
(a) 20% (b) 25% (c) 30% (d) 50%
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(a) The amount of pure acid in 60 oz of 20% acid solution is
(Type an integer or a decimal.)
(b) The amount of pure acid in 60 oz of 25% acid solution is
(Type an integer or a decimal.)
oz.
Student Gradeb
oz.
(b) The amount of pure acid in 60 oz of 30% acid solution is
(Type an integer or a decimal.)
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oz.
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(b) The amount of pure acid in 60 oz of 50% acid solution is
(Type an integer or a decimal.)
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Answer 1

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Explanation:

* Lets explain how to solve the problem

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵ solution ⇒ pure acid

100% 20%

60 The number of ounces

- By using cross multiplication

∴ The number of ounces =
`(60*20)/(100)= 12`

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵ solution ⇒ pure acid

100% 25%

60 The number of ounces

- By using cross multiplication

∴ The number of ounces =
`(60*25)/(100)= 15`

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵ solution ⇒ pure acid

100% 30%

60 The number of ounces

- By using cross multiplication

∴ The number of ounces =
`(60*30)/(100)= 18`

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵ solution ⇒ pure acid

100% 50%

60 The number of ounces

- By using cross multiplication

∴ The number of ounces =
`(60*50)/(100)= 30`

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.