Question

A student took a calibrated 250.0 gram mass, weighed it on a laboratory balance, and found it read 266.5 g. What was the student’s percent error?​

Answer 1

`\boxed{\text{6.60 \%}}`

Step-by-step explanation:

`\text{Percent error} = \frac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} *100 \,\%`

`\text{\% error} = (\lvert 266.5 - 250.0\lvert)/(250.0) * 100 \, \% = (\lvert 16.5\lvert)/(250.0) * 100 \, \% = (16.5)/(250.0) * 100 \,\%\\\\ = 0.0660 * 100 \, \% = \textbf{6.60 \%}\\\text{The student's percent error is $\boxed{\textbf{6.60 \%}}$}`