Question

If g (x)= x+1/x-2 and h(x) =4-c, what is the value of (g•h)(-3)?

Answer 1

Explanation:

g(h(-3)) = g(7)

As h(x)= 4-x so h(-3) = 4+3=7

(g•h)(-3)= g(7) = 7+1/7-2= 8/5

Answer 2

`g(h(-3)) = (8)/(5)`

Explanation:

Given:

`g(x)=(x+1)/(x-2) \\`

`h(x)=4-x`

Find
`g(h(-3))`

What this problem is asking is find the value of
`h(-3)` and then put that answer into
`g(x).`

Let's find
`h(-3)`.

`h(x)=4-x\\h(-3)=4-(-3)\\h(-3)=7`

Now that we found that
`h(-3)` is equal to 7, we put the value of 7 into
`g(x).`

`g(x)=(x+1)/(x-2)\\g(7)=(7+1)/(7-2) \\g(7)=(8)/(5)`

Our final answer is

`g(h(-3)) = (8)/(5)`