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ABCD is a parallelogram. AB = x + 16, AD = 4y – 4, CD = 2x + 8. If the perimeter of ▱ABCD is 80, find the value of y.

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Final answer:

By setting up the perimeter equation for the parallelogram ABCD, solving for x, and then substituting back into the equation, we find that the value of y is 5.

Step-by-step explanation:

To find the value of y for the parallelogram ABCD with a given perimeter of 80, we can sum up the lengths of all its sides and set that equal to the perimeter. Since opposite sides of a parallelogram are equal, we have: AB = CD and AD = BC. Given that AB = x + 16, CD = 2x + 8, and AD (also BC) = 4y - 4, we can write the perimeter equation as:

2(AB) + 2(AD) = Perimeter

2(x + 16) + 2(4y - 4) = 80

Expanding this, we get:

2x + 32 + 8y - 8 = 80

Subtract 32 from both sides and add 8 to both sides we get:

2x + 8y = 56

Since AB is equal to CD, we can also write:

x + 16 = 2x + 8

Subtract x from both sides to find x:

16 = x + 8

x = 8

Plug x back into the perimeter equation:

2(8) + 8y = 56

16 + 8y = 56

Subtract 16 from both sides to isolate 8y:

8y = 40

Divide both sides by 8 to solve for y:

y = 5

Therefore, the value of y is 5.

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