Question

Find the equation of the line containing the points p(2,1) and is parallel to the graph 3x+y=-1.

Answer 1

Explanation:

Slope of a line 3x+y=-1 is -3

So line passing through (2,1) has same slope because both are parallel

From slope intercept form we have

Y-y1 =m(x-1)

Y-1= -3(x-2)

Y-1 = -3x+6

Y+3x = 6+1

Y+3x =7

Which is required equation of a line.

Answer 2

Explanation:

Slope of a line 3x+y=-1 is -3

So line passing through (2,1) has same slope because both are parallel

From slope intercept form we have

Y-y1 =m(x-1)

Y-1= -3(x-2)

Y-1 = -3x+6

Y+3x = 6+1

Y+3x =7

Which is required equation of a line.