Question

Here, we want to become proficient at changing units so that we can perform calculations as needed. The basic heat transfer equation is q = m*Cp*T, where q is the amount of heat added or subtracted, Cp is the constant pressure heat capacity, and T is the change in temperature (T = T2 – T1). For example, we need to heat 100 lbs of water from 25 °C to 75 °C. How much energy must we add to the water if the constant pressure heat capacity of water is 4.18 J/g K? (Give answer in both kJ and BTU)

Answer 1

9500 kJ; 9000 Btu

Step-by-step explanation:

Data:

m = 100 lb

T₁ = 25 °C

T₂ = 75 °C

Calculations:

1. Energy in kilojoules

ΔT = 75 °C - 25 °C = 50 °C = 50 K

`m = \text{100 lb} * \frac{\text{1 kg}}{\text{2.205 lb}} * \frac{\text{1000 g}}{\text{1 kg}}= 4.54 * 10^(4)\text{ g}\\\\\begin{array}{rcl}q & = & mC_{\text{p}}\Delta T\\& = & 4.54 * 10^(4)\text{ g} * 4.18 \text{ J$\cdot$K$^(-1)$g$^(-1)$} * 50 \text{ K}\\ & = & 9.5 * 10^(6)\text{ J}\\ & = & \textbf{9500 kJ}\\\end{array}`

2. Energy in British thermal units

`\text{Energy} = \text{9500 kJ} * \frac{\text{1 Btu}}{\text{1.055 kJ}} = \text{9000 Btu}`