Question

An object completes 10 cycles in 50s.

a. What is the period of its rotation?
b. What is the frequency of its rotation?

Answer 1

.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given parameters:

Number of cycles = 10cycles

Time taken = 50s

Unknown:

Period of its rotation = ?

Frequency of its rotation = ?

Solution:

The period of rotation is the time taken time taken for a body to complete a number of rotation;

Period =
`(t)/(n)`

t is the time

n is the number of cycles

Period =
`(50)/(10)` = 5s

The period is 5s

Now, frequency is the inverse of period;

F =
`(1)/(period)` =
`(1)/(5)` = 0.2Hz