Answer: SECOND OPTION
Explanation:
Given the following equation:
![x^2-36=5x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zt1uw7y4r3fkwjr8j5qillhvf372fvxozh.png)
You can follow these steps in order to find the values of "x" that makes the equation true:
1. Subtract
from both sides of the equation:
![x^2-36-5x=5x-5x\\\\x^2-5x-36=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9s182a4705bdy1vlk8dikl52xd3kinzk7j.png)
2. Factor the equation. Find two numbers whose sum be -5 and whose product be -36. These are 4 and -9:
![(x+4)(x-9)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/frktgvmzz36202jwastwjglklirdrdjked.png)
Then you get:
![x_1=-4\\\\x_2=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/htqeqrapefgox1jtkqbyxo7cms7hn7ppe7.png)
Checking:
![(-4)^2-36=5(-4)\\\\-20=-20](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hpoy7u2xnkjn5iw886dvrqolcffu4fan7j.png)
TRUE
TRUE