Question

Find the coordinates of the vertices of the figure after the given transformation, translation: (x, y)→(x - 4, y + 4)

A) J'(1, 0), N'(5, 0), M'(5, 3), P'(2, 5)
B) J'(-2, 5), N'(2, 5), M'(2, 2), P'(-1, 0)
C) J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1)
D) J'(-1, 0), N'(-5, 0), M'(-5, -3), P'(-2, -5)

Answer 1

option C

Explanation:

Point J is (1,0), N is (5,0) , P is (2,-5), M is (5,-3)

translation: (x, y)→(x - 4, y + 4)

We do the translation of every point. Subtract 4 from x and add 4 with y.

J is (1,0) -> (1-4,0+4) -> (-3,4) J'

N is (5,0) -> (5-4,0+4) -> (1,4) N'

P is (2,-5) -> (2-4,-5+4) -> (-2,-1) P'

M is (5,-3) -> (5-4,-3+4) -> (1,1) M'

Option C is the correct answer

Answer 2

Option C J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1)

Explanation:

we know that

The rule of the translation is

(x,y) -----> (x-4,y+4)

That means ----> The translation is 4 units at left and 4 units up

Find out the coordinates of the pre-image

Observing the figure

J(1,0),N(5,0),M(5,-3),P(2,-5)

Find out the coordinates of the image

Applying the rule of the translation at the coordinates of pre-image

J(1,0) -----> J'(1-4,0+4)

J(1,0) -----> J'(-3,4)

N(5,0) ---> N'(5-4,0+4)

N(5,0) ---> N'(1,4)

M(5,-3)----> M'(5-4,-3+4)

M(5,-3)----> M'(1,1)

P(2,-5) ----> P'(2-4,-5+4)

P(2,-5) ----> P'(-2,-1)

therefore

The coordinates of the image (after the transformation) are

J'(-3, 4), N'(1, 4), M'(1, 1), P'(-2, -1)