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What is the point slope form of the line with slope -1/4 that passes through the point ( -2,9 )

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\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{9})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{1}{4} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{9}=\stackrel{m}{-\cfrac{1}{4}}[x-\stackrel{x_1}{(-2)}]\implies y-9=-\cfrac{1}{4}(x+2)

User AlBeebe
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