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F(x) = x(2x/2)/x(x+5)(x+6)^2

Find the vertical asymptotes?

1 Answer

4 votes

Answer:

x = -5, x = -6

Explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.


\displaystyle F(x)=(x(2x)/(2))/(x(x+5)(x+6))=(x)/((x+5)(x+6))

The denominator will be zero when ...

x + 5 = 0 . . . . at x = -5

x + 6 = 0 . . . . at x = -6

F(x) = x(2x/2)/x(x+5)(x+6)^2 Find the vertical asymptotes?-example-1
User Pumphouse
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