Question

On a coordinate plane, square A B C D is shown. Point A is at (3, 4), point B is at (2, negative 2), point C is at (negative 4, negative 1), and point D is at (negative 3, 5). What is the perimeter of square ABCD? StartRoot 37 EndRoot units 4 StartRoot 37 EndRoot units 28 units 37 units

Answer 1

4 root 37units

Explanation:

gl on the exam

Answer 2

4
`√(37)`

Explanation:

Since the figure is a square, find the length of 1 side and multiply by 4 for perimeter.

Calculate the length of AB using the distance formula.

AB = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = A(3, 4) and (x₂, y₂ ) = B(2, - 2)

AB =
`√((2-3)^2+(-2-4)^2)`

=
`√((-1)^2+(-6)^2)`

=
`√(1+36)`

=
`√(37)`

Hence

perimeter = 4AB = 4
`√(37)`