Answer:
Energy of each proton will be
![5.61* 10^(-26)J](https://img.qammunity.org/2020/formulas/geography/college/ms1twukbygdo77hqc5n3fhpfo7q1xgf954.png)
Step-by-step explanation:
We have given frequency
![\\u =85MHz=85* 10^6Hz](https://img.qammunity.org/2020/formulas/geography/college/w06lmmgrc2k6u2tmqe5v6p5l1s2p7g2u0y.png)
Plank's constant
![h=6.6* 10^(-34)J-sec](https://img.qammunity.org/2020/formulas/geography/college/c536iec7wdp8rgzp1jxo2jmpndl9poib3y.png)
We have to find the energy of proton
We know that energy is given by
, here h is plank's constant and
is frequency
So energy
![E=6.6* 10^(-34)* 85* 10^6=5.61* 10^(-26)J](https://img.qammunity.org/2020/formulas/geography/college/ldmc4n2viuk4nn6hhweofy0t9xhf9d50dp.png)
So energy of each proton will be
![5.61* 10^(-26)J](https://img.qammunity.org/2020/formulas/geography/college/ms1twukbygdo77hqc5n3fhpfo7q1xgf954.png)