Question

A sample of gas has a volume of 20.0 mL at STP. What will the volume be if the temperature is changed to 546 K and the pressure is changed to 2.0 atm.? (show work plz)

Answer 1

The volume did not change, it remained at 20 ml

Further explanation

Given

20 ml a sample gas at STP(273 K, 1 atm)

T₂=546 K

P₂=2 atm

Required

The volume

Solution

Combined gas Law :

`\tt (P_1.V_1)/(T_1)=(P_2.V_2)/(T_2)`

Input the value :

`\tt (1* 20)/(273)=(2* V_2)/(546)\\\\V_2=(1* 20* 546)/(273* 2)\\\\V_2=20~ml`

The volume does not change because the pressure and temperature are increased by the same ratio as the initial conditions (to 2x)