Question

Find the force of attraction between a proton and an electron separated by a distance equal to the radius of the smallest orbit followed by an electron (5 x 10^-11 m) in a hydrogen atom

Answer 1

The answer is
`-9.239 * 10^(-8)\ N =`

Step-by-step explanation:

The definition of electric force between two puntual charges is

`F_e = (K q_1 q_2)/(d^2)`

where

`K = 9 * 10^9\ Nm^2/C^2`.

In this case,

`q_1 = e = 1.602* 10^(-19)\ C`,

`q_2 = -e = -1.602* 10^(-19)\ C`

and

`d = 5 * 10^(-11)\ m`.

So the force is

`F_e = -9.239 * 10^(-8)\ N`

where the negative sign implies force of attraction.