160k views
2 votes
Find the magnitude of vector A = i - 2j + 3k O V14 10 O4

1 Answer

4 votes

Answer:


|A|=√(1^2+(-2)^2+(3)^2)=3.74

Step-by-step explanation:

Given that,

Vector
A=i-2j+3k............(1)

We need to find the magnitude of vector A. Let us suppose vector in the form of, R = xi + yj + zk. Its magnitude is given by :


|R|=√(x^2+y^2+z^2)

In equation (1),

x = 1

y = -2

z = 3

So, the magnitude of vector A is given by :


|A|=√(1^2+(-2)^2+(3)^2)

|A| = 3.74

So, the magnitude of given vector is 3.74. Hence, this is the required solution.

User Evan Shaw
by
8.4k points

Related questions

asked Sep 9, 2020 50.4k views
Daniel Yankowsky asked Sep 9, 2020
by Daniel Yankowsky
8.6k points
1 answer
5 votes
50.4k views
1 answer
5 votes
215k views
2 answers
3 votes
106k views