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An Fm radio station broadcasts at 85 megahertz(MHz) What is the energy of each photon in Joule? Use h=6.6 x 10 to the 34th Js for the Planckconstant

User BinSys
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1 Answer

4 votes

Answer:

561 × 10⁻²⁸ J

Step-by-step explanation:

Data provided in the question:

Frequency of broadcast, f = 85 MHz = 85 × 10⁶ Hz

Plank's constant, h = 6.6 × 10³⁴ Js

Now,

The energy of a photon is calculated as;

Energy = h × f

on substituting the respective values, we get

Energy of the photon = 6.6 × 10⁻³⁴ × 85 × 10⁶

or

The energy of photon = 561 × 10⁻²⁸ J

User Timhaak
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