Answer: The mass of ammonia produced in the reaction is 11.36 g
Step-by-step explanation:
To calculate the number of moles, we use the equation:
.....(1)
Given mass of nitrogen gas = 9.35 g
Molar mass of nitrogen gas = 28 g/mol
Putting values in equation 1, we get:

The chemical reaction for the formation of ammonia from hydrogen and nitrogen follows:

As, hydrogen gas is present in excess. So, it is considered as an excess reagent.
Nitrogen gas is considered as a limiting reagent because it limits the formation of products.
By Stoichiometry of the reaction:
1 mole of nitrogen gas is producing 2 moles of ammonia gas
So, 0.334 moles of nitrogen gas will produce =
of ammonia gas.
Now, calculating the mass of ammonia gas by using equation 1, we get:
Moles of ammonia gas = 0.668 mol
Molar mass of ammonia gas = 17 g/mol
Putting values in equation 1, we get:

Hence, the mass of ammonia produced in the reaction is 11.36 g