Answer:32.24 s
Step-by-step explanation:
Given
mass of runner (m)=51.8 kg
Constant acceleration(a)=
![1.31 m/s^2](https://img.qammunity.org/2020/formulas/physics/college/5evwgqnqlfowhuvehqed9m7gg0l4l7v5nb.png)
Final velocity (v)=5.47 m/s
Time taken taken to reach 5.47 m/s
v=u+at
![5.47=0+1.31* t](https://img.qammunity.org/2020/formulas/physics/college/xoajwspzgwomggzw6ra4yoz7vsbkf491k9.png)
![t=(5.47)/(1.31)=4.17 s](https://img.qammunity.org/2020/formulas/physics/college/qp1eerpkgbx7pv0o4pswqtrnmx2uebp2x7.png)
Distance traveled during this time is
![s=ut+(1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/y4u77sotscfafpxzyglg8hbmefjo11knkz.png)
![s=(1)/(2)* 1.31* 4.17^2=11.42 m](https://img.qammunity.org/2020/formulas/physics/college/4rynkc57zvbjs01dwtxfkwdsznmnbg3lha.png)
So remaining distance left to travel with constant velocity=153.57 m
thus time
![=(distance)/(speed)](https://img.qammunity.org/2020/formulas/physics/college/dy4gl7t74h9r10c396vk9bvxat1ltp1r5q.png)
![t_2=(153.57)/(5.47)=28.07 s](https://img.qammunity.org/2020/formulas/physics/college/n6l9invvlk7g3q6l5dddc0cwip4qfvjc0p.png)
Total time=28.07+4.17=32.24 s