Question

Find the values of the root mean square translational speed v, molecules in gaseous diatomic oxygen (O2), gaseous carbon dioxide (CO2), and gaseous diatomic hydrogen (H2), at temperature 100° C.

Answer 1

For diatomic oxygen:V=539.06 m/s

For carbon dia oxide:V=459.71 m/s

For dia atomic hydrogen:V=2156.25 m/s

Step-by-step explanation:

As we know that

Root mean square velocity V

`V=\sqrt{(3RT)/(M)}`

Where

R is the gas constant

`R=8.31\ (kg.m^2)/(s^2.mol.K)`

T is the temperature (K).

M is the molecular weight.

For diatomic oxygen:

M=32 g/mol

T=273+100 = 373 K

`R=8.31\ (kg.m^2)/(s^2.mol.K)`

`V=\sqrt{(3RT)/(M)}`

`V=\sqrt{(3* 8.31* 373)/(32* 10^(-3))}`

V=539.06 m/s

For carbon dia oxide

M=44 g/mol

T=273+100 = 373 K

`R=8.31\ (kg.m^2)/(s^2.mol.K)`

`V=\sqrt{(3RT)/(M)}`

`V=\sqrt{(3* 8.31* 373)/(44* 10^(-3))}`

V=459.71 m/s

For dia atomic hydrogen:

M= 2 g/mol

T=273+100 = 373 K

`R=8.31\ (kg.m^2)/(s^2.mol.K)`

`V=\sqrt{(3RT)/(M)}`

`V=\sqrt{(3* 8.31* 373)/(2* 10^(-3))}`

V=2156.25 m/s