Question

15 g of anhydrous calcium chloride is dissolved in 185 mL of water. What is molarity of the prepared solution? 81.1 M O0.73 M 0.081 M O0.073 M 1.07 M

Answer 1

When you prepared the solution, you will find that the molarity is 0.73M

Step-by-step explanation:

First of all you should get by the periodic table, molar mass in the anhydrouds calcium.

CaCl2 · 0H20 = 110.98 g/m

Now we have to find out how many mols are 15 g.

So 15g / 110.98 g/m = 0.135 moles

This moles are in 185 ml of water. Molarity as you should know are moles of solute in 1 L of solution (either 1000 ml)

185 ml ______ 0.135 moles

1000 ml _____ x x = (1000*0.135) /185 = 0.730M