Question

Suppose the potential due to a point charge is 6.25x10^2 v at a distance of 17m. What is the magnitude of the charge, in coulombs?

Answer 1

`q=1.18*10^(-6)C}`

Step-by-step explanation:

The potential V due to a charge q, at a distance r, is:

`V=k(q)/(r)`

k=8.99×109 N·m^2/C^2 :Coulomb constant

We solve to find q:

`q=(V*r)/(k)=(6.25*10^(2)*17)/(8.99*10^(9))=1.18*10^(-6)C`