Question

The density of a nuclear matter is about 10^18kg/m^3. given that 1mL is equal in volume to cm^3, what is the density of nuclear matter in megawatts per micrometer that is Mg/uL?

Answer 1

The density of nuclear matter is
`10^(6)\ Mg/\mu L`

Step-by-step explanation:

Given that,

Density
`\rho= 10^(18)\ kg/m^3`

Using unit conversation,

`\Rightarrow (10^(18)\ kg)/(1\ m^3)*(1 Mg)/(10^(6)g)*(1000\ g)/(1\ kg)*(1\ m^3)/(10^6\ cm^3)*(1\ cm^3)/(1\ mL)*(1000\ mL)/(1\ L)*(10^(-6)\ L)/(1\ \muL)`

`\Rightarrow (10^(18)*10^(3)*10^(3)*10^(-6))/(10^(6)*10^(6)*10^(6))`

The density of nuclear matter is

`\rho=10^(6)\ Mg/\mu L`

Hence, The density of nuclear matter is
`10^(6)\ Mg/\mu L`