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Find the critical angle for total internal reflection for a flint glass-air boundary (you may assume that λ = 580.0 nm). Express your answer to 4 significant figures!

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Answer:

the critical angle of the flint glass is 37.04⁰

Step-by-step explanation:

to calculate the critical angle for total internal reflection.

given,

wavelength of the flint glass = λ = 580.0 nm

= 580 × 10⁻⁹ m

critical angle = sin^{-1}(\dfrac{\mu_a}{\mu_g})

at the wavelength of 580.0 nm the refractive index of the glass is 1.66

refractive index of air = 1

critical angle = sin^{-1}(\dfrac{1}{1.66})

= 37.04⁰

hence, the critical angle of the flint glass is 37.04⁰

User Alex Wulff
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