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HOW LONG WILL AN "H" CYLINDER LAST IF IT HAS 1350 PSIG IN IT AND IT RUNS AT 6 LPM?

User Liquinaut
by
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1 Answer

4 votes

Answer:

11.78 hours.

Explanation:

We are asked to find the time that an "H" cylinder will last having 1350 PSI of gas in it at a flow of 6 LPM.


\text{Duration of tank (in minutes)}=\frac{\text{Tank pressure (in PSI)}*\text{Conversion factor}}{\text{Flow (LPM)}}


\text{Duration of H tank (in minutes)}=(1350* 3.14)/(6)


\text{Duration of H tank (in minutes)}=(4239)/(6)


\text{Duration of H tank (in minutes)}=706.5

To convert the time in hours, we will divide 706.5 by 60 as i hour equals 60 minutes.


\text{Duration of H tank (in hours)}=(706.5)/(60)


\text{Duration of H tank (in hours)}=11.775

Therefore, it will take 11.78 hours to last the given cylinder.

User Eyla
by
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