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Light with a wavelength of 494 nm in vacuo travels from vacuum to water. Find the wavelength of the light inside the water in nm (10-9 m). Note that wavelength and speed change when light transfers between media. Frequency does not change. Assume the index of refraction of water is 1.333.

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Answer:

370.6 nm

Step-by-step explanation:

wavelength in vacuum = 494 nm

refractive index of water with respect to air = 1.333

Let the wavelength of light in water is λ.

The frequency of the light remains same but the speed and the wavelength is changed as the light passes from one medium to another.

By using the definition of refractive index


n = (wavelength in air)/(wavelength in water)

where, n be the refractive index of water with respect to air

By substituting the values, we get


1.333 = (494)/(\lambda )

λ = 370.6 nm

Thus, the wavelength of light in water is 370.6 nm.

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