Question

The force of attraction between a -130.0 C and +180.0 C charge is 8.00 N. What is the separation between these two charges in meter rounded to three decimal places? (k = 1/470 - 9.00 10°N.m2/C2 1uC = 106C)

Answer 1

distance between the charges is 5.12 × 10⁶ m

Step-by-step explanation:

charges q₁ = -130.0 C

q₂ = 180 C

force between the charges = 8 N

force between two charge

`F = (k q_1q_2)/(r^2)`

value of K =8.975 × 10⁹ N.m²/C²

`8 = (8.975 * 10^(9)* 130 * 180)/(r^2)`

`r^2 = (8.975 * 10^(9)* 130 * 180)/(8)`

`r^2 =2.625 * 10^(13)`

r = 5.12 × 10⁶ m

hence, distance between the charges is 5.12 × 10⁶ m.