Question

Question 5 (1 point) You need to prepare 1.0 L of solution containing 1.0 mM MgCl2 and 0.15 M NaCl form stock solutions of 1.0 M MgCl2 and 0.50 M NaCl. You will: use 1.0 mL MgCl2, 0.30 L NaCl, fill up with water to 1 L Ouse 100 mL MgCl2, 300 ml NaCl, fill up with water to 1 L use 1.0 mL MgCl2, 30.0 ml NaCl, fill up with water to 1 L use 0.0010 L MgCl2, 0.030 L NaCl, fill up with water to 1 L use 100 ml MgCl2, 300 ml NaCl, fill up with water to 1L

Answer 1

Use 1.0 mL MgCl2, 0.30 L NaCl, fill up with water to 1 L

Step-by-step explanation:

The dilution equation relates the concentration C₁ and volume V₁ of an undiluted solution to the concentration C₂ and volume V₂ as follows:

C₁V₁ = C₂V₂

We want to solve for V₁, the amount of stock solution that is required for the dilution to 1.0L.

V₁ = (C₂V₂) / C₁

For the MgCl₂ stock solution, the following volume is required:

V₁ = (C₂V₂) / C₁ = (1.0mM)(1.0L) / (1.0M) = 1 mL

For the NaCl stock solution, the following volume is required:

V₁ = (C₂V₂) / C₁ = (0.15M)(1.0L) / (0.50M) = 0.30 L

The volumes V₁ are the diluted until the total volume reaches V₂.