Answer:

Explanation:
We know that when two events A and B are independent , then the probability of getting A and B will be :-

In a fair dice,total outcomes =6
Number of 2's =1
Then, the probability of getting a 2 =

If you roll one die two times, then the probability of getting a 2 on the first roll and a 2 on the second roll will be:-

Hence, the probability of getting a 2 on the first roll and a 2 on the second roll=
