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Let the universal set be the set of integers and let A = x^2 ≤ 5. Write A using the roster method.

A = { } --use commas to separate elements in the set

*Finite Math question

User Bayram
by
4.8k points

2 Answers

2 votes

Final answer:

The set A = x^2 ≤ 5, which includes all integers whose squares are less than or equal to 5, is expressed using the roster method as A = { -2, -1, 0, 1, 2 }.

Step-by-step explanation:

The set A includes all integers x such that x squared is less than or equal to 5. To list the set using the roster method, we identify all integers which, when squared, give a result that does not exceed 5.

The integers satisfying x2 ≤ 5 are -2, -1, 0, 1, and 2 because:

  • (-2)2 = 4, which is less than or equal to 5,
  • (-1)2 = 1, which is less than or equal to 5,
  • 02 = 0, which is less than or equal to 5,
  • 12 = 1, which is less than or equal to 5,
  • (2)2 = 4, which is less than or equal to 5.

Therefore, using the roster method, the set A is written as A = { -2, -1, 0, 1, 2 }.

User Aiden Strydom
by
5.4k points
4 votes

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.


A = x

To convert this into roster form, we can find solutions for x

When
x^2\leq 5\\|x|\leq √(5) =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A=
{-2,-1,0,1,2}

User Sarvan
by
5.5k points
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