Answer:
4.56 seconds
63.25 m
Step-by-step explanation:
t = Time taken for the car to stop
u = Initial velocity = 60 km/h = 100 km/h = 100000/3600 = 27.78 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -6.1 m/s²
Time taken by the car to stop
![v=u+at\\\Rightarrow t=(v-u)/(a)\\\Rightarrow t=(0-27.78)/(-6.1)\\\Rightarrow t=4.56\ s](https://img.qammunity.org/2020/formulas/physics/college/apectufpl1z1v1c3ay2p55raiocszh9e99.png)
Time taken by the car to stop is 4.56 seconds
![s=ut+(1)/(2)at^2\\\Rightarrow s=27.78* 4.56+(1)/(2)* -6.1* 4.56^2\\\Rightarrow s=63.25\ m](https://img.qammunity.org/2020/formulas/physics/college/fdtjqqxyzxwv5dzrtt2cuv2k3zxe7s6wjl.png)
The total stopping distance would be 63.25 m