Answer:
Part (a) 10.15 m
Part (b) Rising
Step-by-step explanation:
Given,
- Initial speed of the ball = u = 23.6 m/s
- Height of the crossbar = h = 3.05 m
- Distance between the ball and the cross bar = r = 36.0 m
- Angle of projection =

- Initial velocity of the ball in the horizontal direction =

- Initial velocity of the ball in the vertical direction =

part (a)
Let 't' be the time taken to reach the ball to the cross bar,
In x-direction,

Let y be the height attained by the ball at time t = 2.15 sec,

Now Let H be the height by which the ball is clear the crossbar.

part (b)
At the maximum height the vertical velocity of the ball becomes zero.
i,e,

Let h be the maximum height attained by the ball.

Hence at the cross bar the ball attains the height 13.205 m but the maximum height is 14.19 m. Therefore the ball is rising when it reaches at the crossbar.