Question

A block is placed at the top of a frictionless inclined plane with angle 30 degrees and released. The incline has a height of 15 m and the block has mass 2 kg. In the above problem the speed of the block when it reaches the bottom of the incline is 8.3 m/s 17 m/s 25 m/s 30 m/s

Answer 1

The speed of the block when it reaches the bottom is 17 m/s.

(b) is correct option.

Step-by-step explanation:

Given that,

Height = 15 m

Mass = 2 kg

We need to calculate the speed of the block when it reaches the bottom

Using conservation of energy

`mgh=(1)/(2)mv^2`

`v^2=2gh`

`v=√(2gh)`

Where, g = acceleration due to gravity

h = height

Put the value into the formula

`v=√(2*9.8*15)`

`v=17\ m/s`

Hence, The speed of the block when it reaches the bottom is 17 m/s.