Question

A rifle with a mass of 0.9 kg fires a bullet with a mass of 6.0 g (0.006 kg). The bullet moves with a muzzle velocity of 750 m/s after the rifle is fired a. What is the momentum of the bullet after the rifle is fired? b. If external forces acting on the rifle can be ignored, what is the recoil velocity of the rifle?

Answer 1

a ) 4.5 N.s

b) V =5 m/s

Step-by-step explanation:

given,

mass of rifle(M) = 0.9 kg

mass of bullet(m) = 6 g = 0.006 kg

velocity of the bullet(v) = 750 m/s

a) momentum of bullet = m × v

= 750 × 0.006

= 4.5 N.s

b) recoil velocity

m × u + M × U = m × v + M × V

0 + 0 = 0.006 × 750 - 0.9 × V

V =
`(4.5)/(0.9)`

V =5 m/s