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A 0.676 m long section of cable carrying current to a car starter motor makes an angle of 57.7º with the Earth’s 5.29 x 10^−5T field. What is the current when the wire experiences a force of 6.53 x 10^−3 N?

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Answer:

The current in the wire under the influence of the force is 216.033 A

Solution:

According to the question:

Length of the wire, l = 0.676 m


\theta = 57.7^(\circ)

Magnetic field of the Earth,
B_(E) = 5.29* 10^(- 5) T

Forces experienced by the wire,
F_(m) = 6.53* 10^(-3) N

Also, we know that the force in a magnetic field is given by:


F_(m) = IB_(E)lsin\theta


I = (F_(m))/(B_(E)lsin\theta)


I = \frac{6.53* 10^(-3)}{5.29* 10^(- 5)* 0.676sin57.7^(\circ)

I = 216.033 A

User Andre Evangelista
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