Question

We attach two blocks of masses m1 = 7 kg and m2 = 7 kg to either end of a spring of spring constant k = 1 N/m and set them into oscillation. Calculate the angular frequency ω of the oscillation.

Answer 1

The angular frequency
`\omega` of the oscillation is
`0.58s^(-1)`

Step-by-step explanation:

For this particular situation, the angular frequency of the system is given by

`\omega=\sqrt{(m_1+m_2)/(m_1m_2)k}=\sqrt{(7 kg+5 kg )/(7kg *5 kg)1(N)/(m)}=\sqrt{(3)/(35s^2)}\approx 0.58s^(-1)`