Answer:
weeks
Explanation:
The mass of this particular substance can be modeled by the following exponential function:

In which
is the mass in function of time,
is the initial mass and r, in decimal, is the growth rate of the mass.
The problem states that:
The mass of a particular substance is known to grow exponentially at a rate of 17% per week. Its initial mass was 12 grams and, after t weeks, it weighed 56 grams. So:



We have to solve this equation for t. So:




To solve for
, we put ln in both sides



weeks