Question

Two 1.1 kg masses are 1 m apart (center to center) on a frictionless table. Each has +10 JC of charge. What is the initial acceleration (in m/s2) of this massif it is released and allowed to move?

Answer 1

acceleration = 0.8181 m/s²

Step-by-step explanation:

given data

mass = 1.1 kg

apart d = 1 m

charge q = 10 μC

to find out

What is the initial acceleration

solution

we know that acceleration is

acceleration =
`(force)/(mass)` .................1

here force =
`k (q1q2)/(r^2)`

here q1 q2 is charge and r is distance and Coulomb constant k = 9 ×
`10^(9)` Nm²/C²

force =
`9*10^(9) ((10*10^(-6))^2)/(1^2)`

force = 0.9 N

so from equation 1

acceleration =
`(0.9)/(1.1)`

acceleration = 0.8181 m/s²